# Line slope calculator 2x+10y=80

**Straight line given by points A[0; 8] and B[10; 6]**

## Calculation:

**Slope-intercept form of line:**y = -0.2x+8

**Canonical form of the line equation:**2x+10y-80 = 0

**Parametric form of the line equation:**

x = 10t

y = -2t+8 ; t ∈ R

**Slope:**m = -0.2

**Slope angle of line: φ =**-11°18'36″ = -0.1974 rad

**X intercept:**x

_{0}= 40

**Y intercept:**y

_{0}= q = 8

**Distance line from the origin:**d

_{0}= 7.8446

**The length of the segment AB: |AB| =**10.198

**Vector: AB =**(10; -2)

**Normal vector: n =**(2; 10)

**Midpoint of the segment AB: M =**[5; 7]

**Perpendicular Bisector equation:**10x-2y-36 = 0

**Vector OA = (0; 8) ; |OA| = 8**

**Vector OB = (10; 6) ; |OB| = 11.6619**

**Scalar product OA .OB = 48**

**Angle ∠ AOB = 59°2'10″ = 1.0304 rad**